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The director of admissions of a small college selected 120 students at random from the new freshman class in a study to determine whether a student’s grade point average (GPA) at the end of the freshman year (Y) can be predicted from the ACT test score (X). So the director would like to fit a simple linear regression on Y and X.Based on the summary statistics below, please calculate the estimate of .=2666=2385.328=368.886=1183.379 = 93.928

Question

The director of admissions of a small college selected 120 students at random from the new freshman class in a study to determine whether a student’s grade point average (GPA) at the end of the freshman year (Y) can be predicted from the ACT test score (X). So the director would like to fit a simple linear regression on Y and X.Based on the summary statistics below, please calculate the estimate of .=2666=2385.328=368.886=1183.379 = 93.928

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Solution

The estimate of the slope (b1) in a simple linear regression can be calculated using the formula:

b1 = (ΣXY - nȲ) / (ΣX^2 - n*X̄^2)

where: ΣXY is the sum of the product of X and Y, n is the number of observations, X̄ is the mean of X, Ȳ is the mean of Y, ΣX^2 is the sum of the squares of X.

Given the summary statistics:

ΣX = 2385.328 ΣY = 2666 ΣXY = 368.886 ΣX^2 = 1183.379 n = 120

First, calculate the means of X and Y:

X̄ = ΣX / n = 2385.328 / 120 = 19.87773 Ȳ = ΣY / n = 2666 / 120 = 22.21667

Then, substitute these values into the formula for b1:

b1 = (ΣXY - nȲ) / (ΣX^2 - nX̄^2) b1 = (368.886 - 12019.8777322.21667) / (1183.379 - 12019.87773^2)

After calculating the above expression, you will get the estimate of b1.

This problem has been solved

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