The problem is asking to reverse every k nodes in a linked list. Here is a step-by-step solution in Python:

1. Define a function `reverseK` that takes a linked list and an integer k as input.

```python
def reverseK(head, k):
```

2. Initialize three pointers: `prev` as `None`, `next` as `None`, and `current` as `head`.

```python
current = head
next = None
prev = None
count = 0
```

3. Traverse the linked list. Reverse the links until `count` becomes `k`.

```python
while(current is not None and count

Question

The problem is asking to reverse every k nodes in a linked list. Here is a step-by-step solution in Python:

1. Define a function `reverseK` that takes a linked list and an integer k as input.

```python
def reverseK(head, k):
```

2. Initialize three pointers: `prev` as `None`, `next` as `None`, and `current` as `head`.

```python
    current = head
    next = None
    prev = None
    count = 0
```

3. Traverse the linked list. Reverse the links until `count` becomes `k`.

```python
    while(current is not None and count < k):
        next = current.next
        current.next = prev
        prev = current
        current = next
        count += 1
```

4. Now `next` is pointing to `(k+1)th` node. Recursively call for the list starting from `next`. And make rest of the list as next of first node.

```python
    if next is not None:
        head.next = reverseK(next, k)
```

5. Change next of last node in the list to `prev`.

```python
    return prev
```

6. Call the function `reverseK` with the head of the linked list and `k` as arguments.

```python
head = reverseK(head, k)
```

7. Print the modified linked list.

```python
while(head):
    print(head.data, end=" ")
    head = head.next
```

This solution works by reversing the first `k` nodes of the linked list, then recursively reversing the next `k` nodes, until all nodes have been reversed. The time complexity is O(n), where n is the number of nodes in the linked list.

Knowee AI · Accepted Answer