Here is a step-by-step solution to the problem:

1. Initialize two variables, `chairs` and `people`, to 0. `chairs` will keep track of the number of chairs needed and `people` will keep track of the number of people in the room.

2. Iterate over the string `s` from left to right. For each character `s[i]`:

- If `s[i]` is 'E', increment `people` by 1. If `people` is greater than `chairs`, increment `chairs` by 1. This means a new person has entered the room and if there are not enough chairs, we add one.

- If `s[i]` is 'L', decrement `people` by 1. This means a person has left the room, freeing up a chair.

3. After iterating over the entire string, `chairs` will hold the minimum number of chairs needed so that a chair is available for every person who enters the waiting room.

Here is a Python code snippet that implements the above steps:

```python
def min_chairs(s):
chairs = people = 0
for i in s:
if i == 'E':
people += 1
if people chairs:
chairs += 1
else:
people -= 1
return chairs
```

You can call this function with the string `s` as the argument to get the minimum number of chairs needed.

Question

Here is a step-by-step solution to the problem:

1. Initialize two variables, `chairs` and `people`, to 0. `chairs` will keep track of the number of chairs needed and `people` will keep track of the number of people in the room.

2. Iterate over the string `s` from left to right. For each character `s[i]`:

- If `s[i]` is 'E', increment `people` by 1. If `people` is greater than `chairs`, increment `chairs` by 1. This means a new person has entered the room and if there are not enough chairs, we add one.
   
   - If `s[i]` is 'L', decrement `people` by 1. This means a person has left the room, freeing up a chair.

3. After iterating over the entire string, `chairs` will hold the minimum number of chairs needed so that a chair is available for every person who enters the waiting room.

Here is a Python code snippet that implements the above steps:

```python
def min_chairs(s):
    chairs = people = 0
    for i in s:
        if i == 'E':
            people += 1
            if people > chairs:
                chairs += 1
        else:
            people -= 1
    return chairs
```

You can call this function with the string `s` as the argument to get the minimum number of chairs needed.

Knowee AI · Accepted Answer

Here is a step-by-step solution to the problem:

1. Initialize two variables, `chairs` and `people`, to 0. `chairs` will keep track of the number of chairs needed and `people` will keep track of the number of people in the room.

2. Iterate over the string `s` from left to right. For each character `s[i]`:

- If `s[i]` is 'E', increment `people` by 1. If `people` is greater than `chairs`, increment `chairs` by 1. This means a new person has entered the room and if there are not enough chairs, we add one.
   
   - If `s[i]` is 'L', decrement `people` by 1. This means a person has left the room, freeing up a chair.

3. After iterating over the entire string, `chairs` will hold the minimum number of chairs needed so that a chair is available for every person who enters the waiting room.

Here is a Python code snippet that implements the above steps:

```python
def min_chairs(s):
    chairs = people = 0
    for i in s:
        if i == 'E':
            people += 1
            if people > chairs:
                chairs += 1
        else:
            people -= 1
    return chairs
```

You can call this function with the string `s` as the argument to get the minimum number of chairs needed.

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