Let's denote the number of copper pipes as C and the number of plastic pipes as P.

From the problem, we have two equations:

1) C + P = 7 (since the plumber bought 7 pieces of pipe in total)

2) 2C + 3P = 19 (since each copper pipe is 2 metres long and each plastic pipe is 3 metres long, and the total length of the pipe was 19 metres)

We can solve these equations step by step:

First, let's isolate C in the first equation:

C = 7 - P

Now, we substitute C from the first equation into the second equation:

2(7 - P) + 3P = 19
14 - 2P + 3P = 19
P = 19 - 14 = 5

Substitute P = 5 into the first equation:

C = 7 - 5 = 2

So, the plumber bought 2 pieces of copper pipe and 5 pieces of plastic pipe.

Question

Let's denote the number of copper pipes as C and the number of plastic pipes as P.

From the problem, we have two equations:

1) C + P = 7 (since the plumber bought 7 pieces of pipe in total)

2) 2C + 3P = 19 (since each copper pipe is 2 metres long and each plastic pipe is 3 metres long, and the total length of the pipe was 19 metres)

We can solve these equations step by step:

First, let's isolate C in the first equation:

C = 7 - P

Now, we substitute C from the first equation into the second equation:

2(7 - P) + 3P = 19
14 - 2P + 3P = 19
P = 19 - 14 = 5

Substitute P = 5 into the first equation:

C = 7 - 5 = 2

So, the plumber bought 2 pieces of copper pipe and 5 pieces of plastic pipe.

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