A half wave controlled rectifier is used in certain application is connected to an AC Voltage : v(t) = 300sin(314.159t). The average value of the output voltage from such a converter at a resistive load of 3kW at a Firing angle of 60 degrees is....Select one:a. 95.5b. 144 Vc. 72 Vd. 47.75 V
Question
A half wave controlled rectifier is used in certain application is connected to an AC Voltage : v(t) = 300sin(314.159t). The average value of the output voltage from such a converter at a resistive load of 3kW at a Firing angle of 60 degrees is....Select one:a. 95.5b. 144 Vc. 72 Vd. 47.75 V
Solution
The average output voltage (Vavg) of a half-wave controlled rectifier can be calculated using the following formula:
Vavg = (2Vm/pi) * (1 + cos(alpha))
Where:
- Vm is the peak voltage, which can be calculated from the given RMS voltage using the formula Vm = Vrms * sqrt(2). In this case, Vrms = 300V, so Vm = 300 * sqrt(2) = 424.26V.
- alpha is the firing angle, which is given as 60 degrees.
Substituting these values into the formula gives:
Vavg = (2 * 424.26/pi) * (1 + cos(60)) = 269.5 * (1 + 0.5) = 269.5 * 1.5 = 404.25V
However, this value does not match any of the options given in the question. It's possible that there may be a mistake in the question or in the given options.
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