The graphs of f(x) = x^2-3x-1 and g(x) = 3+5x-x^2 are shown.Vertical lines are places between f and g between between f and g.a. Find the coordinates of the points of intersections between f and g.b. Find the value of x for which the line between the two functions is the largest. c. Find the length of the longest line.
Question
The graphs of f(x) = x^2-3x-1 and g(x) = 3+5x-x^2 are shown.Vertical lines are places between f and g between between f and g.a. Find the coordinates of the points of intersections between f and g.b. Find the value of x for which the line between the two functions is the largest. c. Find the length of the longest line.
Solution
a. To find the points of intersection between f(x) = x^2 - 3x - 1 and g(x) = 3 + 5x - x^2, we need to set the two functions equal to each other and solve for x:
x^2 - 3x - 1 = 3 + 5x - x^2
Combine like terms:
2x^2 - 8x - 4 = 0
Divide the equation by 2 to simplify:
x^2 - 4x - 2 = 0
This is a quadratic equation in the form ax^2 + bx + c = 0. We can solve for x using the quadratic formula x = [-b ± sqrt(b^2 - 4ac)] / (2a):
x = [4 ± sqrt((-4)^2 - 4*(-2))] / 2 x = [4 ± sqrt(16 + 8)] / 2 x = [4 ± sqrt(24)] / 2 x = [4 ± 2sqrt(6)] / 2 x = 2 ± sqrt(6)
So the points of intersection are (2 - sqrt(6), f(2 - sqrt(6))) and (2 + sqrt(6), f(2 + sqrt(6))).
b. The line between the two functions is the largest when the difference between the two functions is the largest. This occurs when the derivative of the difference between the two functions is zero. The difference between the two functions is:
h(x) = g(x) - f(x) = (3 + 5x - x^2) - (x^2 - 3x - 1) = 8x - 2x^2 + 4
The derivative of h(x) is:
h'(x) = 8 - 4x
Setting h'(x) = 0 gives:
8 - 4x = 0 4x = 8 x = 2
So the line between the two functions is the largest when x = 2.
c. The length of the longest line is the difference between the two functions at x = 2:
|f(2) - g(2)| = |(2^2 - 32 - 1) - (3 + 52 - 2^2)| = |4 - 6 - 1 - 3 - 10 + 4| = |-1 - 9| = |-10| = 10
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