Solve the system by substitution.minus, 4, x, plus, 8, y, equals, 40−4x+8y=40minus, 2, x, equals, y−2x=y
Question
Solve the system by substitution.minus, 4, x, plus, 8, y, equals, 40−4x+8y=40minus, 2, x, equals, y−2x=y
Solution
Step 1: We have two equations here:
-4x + 8y = 40 -2x = y
Step 2: From the second equation, we can express y in terms of x:
y = -2x
Step 3: Substitute y = -2x into the first equation:
-4x + 8(-2x) = 40 -4x - 16x = 40 -20x = 40
Step 4: Solve for x:
x = 40 / -20 x = -2
Step 5: Substitute x = -2 into the second equation to find y:
y = -2(-2) y = 4
So, the solution to the system of equations is x = -2 and y = 4.
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