Watch your weight: A study published in 2008 reported that the mean weight of men aged 40-59 was 89.3 kg. Another study, published in 2016, reported that a sample of 192 men aged 40-59 had an average weight of 87 kg. Assume the population standard deviation is =σ14.2 kg. Can you conclude that the mean weight of men aged 40-59 is lower in 2016 than in 2008? Use the =α0.05 level of significance.Part 1 of 5(a) State the appropriate null and alternate hypotheses.H0: =μ89.3H1: <μ89.3The hypothesis test is a ▼left-tailed test.Part: 1 / 51 of 5 Parts CompletePart 2 of 5(b) Compute the value of the test statistic. Round your answer to two decimal places.z=
Question
Watch your weight: A study published in 2008 reported that the mean weight of men aged 40-59 was 89.3 kg. Another study, published in 2016, reported that a sample of 192 men aged 40-59 had an average weight of 87 kg. Assume the population standard deviation is =σ14.2 kg. Can you conclude that the mean weight of men aged 40-59 is lower in 2016 than in 2008? Use the =α0.05 level of significance.Part 1 of 5(a) State the appropriate null and alternate hypotheses.H0: =μ89.3H1: <μ89.3The hypothesis test is a ▼left-tailed test.Part: 1 / 51 of 5 Parts CompletePart 2 of 5(b) Compute the value of the test statistic. Round your answer to two decimal places.z=
Solution
The null hypothesis (H0) and alternate hypothesis (H1) are as follows:
H0: μ = 89.3 (The mean weight of men aged 40-59 in 2016 is the same as in 2008) H1: μ < 89.3 (The mean weight of men aged 40-59 in 2016 is less than in 2008)
This is a left-tailed test because we are testing if the mean weight in 2016 is less than the mean weight in 2008.
To compute the value of the test statistic (z), we use the formula:
z = (X - μ) / (σ / √n)
where: X = sample mean = 87 kg μ = population mean = 89.3 kg σ = population standard deviation = 14.2 kg n = sample size = 192
Substituting the values into the formula, we get:
z = (87 - 89.3) / (14.2 / √192)
After calculating, round your answer to two decimal places.
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