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In ∆𝐴𝐵𝐶, ∠𝐴 + ∠𝐵 = 650 and ∠B + ∠C = 1400. What is the value of∠B

Question

In ∆𝐴𝐵𝐶, ∠𝐴 + ∠𝐵 = 650 and ∠B + ∠C = 1400. What is the value of∠B

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Solution

To find the value of ∠B, we can use the given information:

∠A + ∠B = 65° and ∠B + ∠C = 140°

We know that in any triangle, the sum of the three angles is always 180°. So, ∠A + ∠B + ∠C = 180°

We can substitute ∠A + ∠B = 65° into this equation to get 65° + ∠C = 180°, which simplifies to ∠C = 180° - 65° = 115°

Now we can substitute ∠C = 115° into the equation ∠B + ∠C = 140° to get ∠B + 115° = 140°, which simplifies to ∠B = 140° - 115° = 25°

So, the value of ∠B is 25°.

This problem has been solved

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