In ∆𝐴𝐵𝐶, ∠𝐴 + ∠𝐵 = 650 and ∠B + ∠C = 1400. What is the value of∠B
Question
In ∆𝐴𝐵𝐶, ∠𝐴 + ∠𝐵 = 650 and ∠B + ∠C = 1400. What is the value of∠B
Solution
To find the value of ∠B, we can use the given information:
∠A + ∠B = 65° and ∠B + ∠C = 140°
We know that in any triangle, the sum of the three angles is always 180°. So, ∠A + ∠B + ∠C = 180°
We can substitute ∠A + ∠B = 65° into this equation to get 65° + ∠C = 180°, which simplifies to ∠C = 180° - 65° = 115°
Now we can substitute ∠C = 115° into the equation ∠B + ∠C = 140° to get ∠B + 115° = 140°, which simplifies to ∠B = 140° - 115° = 25°
So, the value of ∠B is 25°.
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