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e correct answerWhat will be the output of the following Java code?  class Codetantra  {    final public int output(int x, int y) { return 1; }   }   class Program extends Codetantra   {     public int output(int x, int y) { return 2; }   }    public class result   {    public static void main(String args[])     {       Program object = new Program();       System.out.print("y is " + y.output(0, 1));      }   }

Question

e correct answerWhat will be the output of the following Java code?  class Codetantra  {    final public int output(int x, int y) { return 1; }   }   class Program extends Codetantra   {     public int output(int x, int y) { return 2; }   }    public class result   {    public static void main(String args[])     {       Program object = new Program();       System.out.print("y is " + y.output(0, 1));      }   }

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Solution

The code will not compile. The method output(int x, int y) in the Program class is attempting to override the output(int x, int y) method in the Codetantra class. However, the output(int x, int y) method in the Codetantra class is declared as final, which means it cannot be overridden.

Additionally, the variable y is not defined in the main method. If you meant to call the output method on the object instance of Program, you should replace y.output(0, 1) with object.output(0, 1).

So, the correct code should be:

class Codetantra { 
    final public int output(int x, int y) { return 1; } 
} 

class Program extends Codetantra { 
    // This method cannot override the final method from Codetantra
    // public int output(int x, int y) { return 2; } 
} 

public class result { 
    public static void main(String args[]) { 
        Program object = new Program(); 
        System.out.print("y is " + object.output(0, 1)); 
    } 
}

This will compile and run, printing "y is 1" to the console.

This problem has been solved

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