You have been given the following code:String[] values = new String[3];Which of the following is an incorrect way to iterate through the collection?a.for (int i = 0; i < values.length; i++)b.for (String temp : values){ }c.int i = 0;while (i < values.length){ i++;}d.Iterator<String> it = values.iterator();while (it.hasNext()){ }

What is the new method introduced in java 8 to iterate through a collection?*1 pointA List.for()B StringList.forEach()C foreach(String i : StringList)D for(String i : StringList)

4Which of the following can be used to iterate through lists or sets in a for loop?A.Iterable stringB.Loop constructC.Iterable variableD.Index variable

What is the output of the following code?import java.util.*;public class Main { public static void main(String[] args) { List list = new ArrayList<>(); list.add(1); list.add(2); list.add(3); Iterator iterator = list.iterator(); while (iterator.hasNext()) { Integer value = iterator.next(); if (value == 2) { iterator.remove(); } } System.out.println(list); }}a)[2, 3]b)[3, 2, 1]c)[1, 2, 3]d)[1, 3]

Consider the following code:ArrayList<String> shapes = new ArrayList<String>(); Iterator<String> shapesIterator = shapes.iterator(); Which of the following is not true?Question 7Answera.shapes is an ArrayList of Stringsb.shapesIterator is an iterator object belonging to shapesc.For Java arrays and ArrayLists the highest index of an array = the number of elements in the array – 1d.the next() method is used to check if there are any more objects in the shapes collectione.the remove() method can be used to delete an object from the shapes collectionf.all of the above are true

What is the output of the following program:import java.util.*;class TestJavaCollection1 { public static void main(String args[]) { ArrayList<String> list = new ArrayList<String>(); // Creating arraylist list.add("Apple"); // Adding object in arraylist list.add("Orange"); list.add("Strawberry"); list.add("Apple"); // Traversing list through Iterator Iterator itr = list.iterator(); while (itr.hasNext()) { System.out.println(itr.next()); } }}