Determine the line current lag in polar form for the circuit of Figure. This is a positive sequence balanced, three-phase system with Van = 208 <30 V and Z₁ = 6 + j8 Ω
Question
Determine the line current lag in polar form for the circuit of Figure. This is a positive sequence balanced, three-phase system with Van = 208 <30 V and Z₁ = 6 + j8 Ω
Solution
To determine the line current lag in polar form for the circuit, we need to follow these steps:
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First, we need to convert the impedance Z₁ from rectangular form to polar form. The magnitude of Z₁ is √(6² + 8²) = 10 Ω and the angle is arctan(8/6) = 53.13°. So, Z₁ = 10 < 53.13° Ω.
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Next, we use Ohm's law for each phase, which states that the current I is equal to the voltage V divided by the impedance Z. In this case, the phase voltage Van is given as 208 < 30° V and the impedance Z₁ is 10 < 53.13° Ω.
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We divide the magnitudes: 208 / 10 = 20.8 A.
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We subtract the angles: 30° - 53.13° = -23.13°.
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So, the line current Ia = 20.8 < -23.13° A.
This means the line current lags the voltage by 23.13°.
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