What is the output of the following few lines of code?1234x=0while(x<2): print(x) x=x+1 1 point010120134
Question
What is the output of the following few lines of code?1234x=0while(x<2): print(x) x=x+1 1 point010120134
Solution
The output of the given code will be:
0 1
Explanation: The code is written in Python and it's a simple while loop. The variable 'x' is initially set to 0. The condition for the while loop is 'x<2' which means the loop will continue to run as long as 'x' is less than 2. Inside the loop, it first prints the current value of 'x' and then increments 'x' by 1. So, in the first iteration, it prints 0 and in the second iteration, it prints 1. After the second iteration, 'x' becomes 2 which is not less than 2, so the loop stops. Hence, the output is 0 and 1.
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