Understanding Precedence & Associativity of operators#include <stdio.h>void main() { char a = 'A'; char b = 'B'; int c = a + b % 3 - 3 * 2; printf("%d\n", c);}What is the value of C =
Question
Understanding Precedence & Associativity of operators#include <stdio.h>void main() { char a = 'A'; char b = 'B'; int c = a + b % 3 - 3 * 2; printf("%d\n", c);}What is the value of C =
Solution
The value of c is calculated as follows:
First, the ASCII values of a and b are used in the calculation. The ASCII value of 'A' is 65 and 'B' is 66.
The expression a + b % 3 - 3 * 2 is evaluated using operator precedence and associativity rules.
The precedence of operators in C is as follows (from highest to lowest):
- Parentheses
() - Unary operators
+-!~ - Arithmetic operators
*/% - Arithmetic operators
+- - Shift operators
<<>> - Relational operators
<<=>>= - Equality operators
==!= - Bitwise AND operator
& - Bitwise XOR operator
^ - Bitwise OR operator
| - Logical AND operator
&& - Logical OR operator
|| - Conditional operator
?: - Assignment operators
=+=-=*=/=%=<<=>>=&=^=|= - Comma operator
,
In your expression, the modulus operator % and the multiplication operator * have higher precedence than the addition operator + and the subtraction operator -.
So, b % 3 and 3 * 2 are evaluated first.
b % 3 is 66 % 3 which equals 0.
3 * 2 equals 6.
Then, the expression becomes a + 0 - 6.
The addition and subtraction are evaluated from left to right (associativity rule), so a + 0 is evaluated first.
a + 0 is 65 + 0 which equals 65.
Then, 65 - 6 equals 59.
So, the value of c is 59.
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