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Understanding Precedence & Associativity of operators#include <stdio.h>void main() { char a = 'A'; char b = 'B'; int c = a + b % 3 - 3 * 2; printf("%d\n", c);}What is the value of C =

Question

Understanding Precedence & Associativity of operators#include <stdio.h>void main() { char a = 'A'; char b = 'B'; int c = a + b % 3 - 3 * 2; printf("%d\n", c);}What is the value of C =

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Solution

The value of c is calculated as follows:

First, the ASCII values of a and b are used in the calculation. The ASCII value of 'A' is 65 and 'B' is 66.

The expression a + b % 3 - 3 * 2 is evaluated using operator precedence and associativity rules.

The precedence of operators in C is as follows (from highest to lowest):

  1. Parentheses ()
  2. Unary operators + - ! ~
  3. Arithmetic operators * / %
  4. Arithmetic operators + -
  5. Shift operators << >>
  6. Relational operators < <= > >=
  7. Equality operators == !=
  8. Bitwise AND operator &
  9. Bitwise XOR operator ^
  10. Bitwise OR operator |
  11. Logical AND operator &&
  12. Logical OR operator ||
  13. Conditional operator ?:
  14. Assignment operators = += -= *= /= %= <<= >>= &= ^= |=
  15. Comma operator ,

In your expression, the modulus operator % and the multiplication operator * have higher precedence than the addition operator + and the subtraction operator -.

So, b % 3 and 3 * 2 are evaluated first.

b % 3 is 66 % 3 which equals 0.

3 * 2 equals 6.

Then, the expression becomes a + 0 - 6.

The addition and subtraction are evaluated from left to right (associativity rule), so a + 0 is evaluated first.

a + 0 is 65 + 0 which equals 65.

Then, 65 - 6 equals 59.

So, the value of c is 59.

This problem has been solved

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