Sure, let's solve this step by step.

Step 1: Find the total resistance in the circuit.
The total resistance (R_total) in the circuit is the sum of the internal resistance of the battery (r) and the load resistance (R). So, R_total = r + R = 0.05 Ω + 1.1 Ω = 1.15 Ω.

Step 2: Find the current in the circuit.
The current (I) in the circuit can be found using Ohm's law, which states that the current is equal to the voltage (V) divided by the resistance (R). So, I = V / R_total = 12.0 V / 1.15 Ω = 10.43 A.

Step 3: Find the terminal voltage of the battery.
The terminal voltage (V_t) of the battery is equal to the emf of the battery minus the product of the current and the internal resistance of the battery. So, V_t = V - I*r = 12.0 V - 10.43 A * 0.05 Ω = 11.48 V.

Step 4: Calculate the power delivered to the load resistor.
The power (P_R) delivered to the load resistor can be found using the formula P = I^2 * R. So, P_R = (10.43 A)^2 * 1.1 Ω = 119.32 W.

Step 5: Calculate the power delivered to the internal resistance of the battery.
The power (P_r) delivered to the internal resistance of the battery can be found using the same formula as in step 4, but with the internal resistance instead of the load resistance. So, P_r = (10.43 A)^2 * 0.05 Ω = 5.43 W.

Step 6: Calculate the power delivered by the battery.
The power (P) delivered by the battery is equal to the product of the current and the emf of the battery. So, P = I * V = 10.43 A * 12.0 V = 125.16 W.

So, the terminal voltage of the battery is 11.48 V, the power delivered to the load resistor is 119.32 W, the power delivered to the internal resistance of the battery is 5.43 W, and the power delivered by the battery is 125.16 W.

Question

Sure, let's solve this step by step.

Step 1: Find the total resistance in the circuit.
The total resistance (R_total) in the circuit is the sum of the internal resistance of the battery (r) and the load resistance (R). So, R_total = r + R = 0.05 Ω + 1.1 Ω = 1.15 Ω.

Step 2: Find the current in the circuit.
The current (I) in the circuit can be found using Ohm's law, which states that the current is equal to the voltage (V) divided by the resistance (R). So, I = V / R_total = 12.0 V / 1.15 Ω = 10.43 A.

Step 3: Find the terminal voltage of the battery.
The terminal voltage (V_t) of the battery is equal to the emf of the battery minus the product of the current and the internal resistance of the battery. So, V_t = V - I*r = 12.0 V - 10.43 A * 0.05 Ω = 11.48 V.

Step 4: Calculate the power delivered to the load resistor.
The power (P_R) delivered to the load resistor can be found using the formula P = I^2 * R. So, P_R = (10.43 A)^2 * 1.1 Ω = 119.32 W.

Step 5: Calculate the power delivered to the internal resistance of the battery.
The power (P_r) delivered to the internal resistance of the battery can be found using the same formula as in step 4, but with the internal resistance instead of the load resistance. So, P_r = (10.43 A)^2 * 0.05 Ω = 5.43 W.

Step 6: Calculate the power delivered by the battery.
The power (P) delivered by the battery is equal to the product of the current and the emf of the battery. So, P = I * V = 10.43 A * 12.0 V = 125.16 W.

So, the terminal voltage of the battery is 11.48 V, the power delivered to the load resistor is 119.32 W, the power delivered to the internal resistance of the battery is 5.43 W, and the power delivered by the battery is 125.16 W.

Knowee AI · Accepted Answer

Sure, let's solve this step by step.

Step 1: Find the total resistance in the circuit.
The total resistance (R_total) in the circuit is the sum of the internal resistance of the battery (r) and the load resistance (R). So, R_total = r + R = 0.05 Ω + 1.1 Ω = 1.15 Ω.

Step 2: Find the current in the circuit.
The current (I) in the circuit can be found using Ohm's law, which states that the current is equal to the voltage (V) divided by the resistance (R). So, I = V / R_total = 12.0 V / 1.15 Ω = 10.43 A.

Step 3: Find the terminal voltage of the battery.
The terminal voltage (V_t) of the battery is equal to the emf of the battery minus the product of the current and the internal resistance of the battery. So, V_t = V - I*r = 12.0 V - 10.43 A * 0.05 Ω = 11.48 V.

Step 4: Calculate the power delivered to the load resistor.
The power (P_R) delivered to the load resistor can be found using the formula P = I^2 * R. So, P_R = (10.43 A)^2 * 1.1 Ω = 119.32 W.

Step 5: Calculate the power delivered to the internal resistance of the battery.
The power (P_r) delivered to the internal resistance of the battery can be found using the same formula as in step 4, but with the internal resistance instead of the load resistance. So, P_r = (10.43 A)^2 * 0.05 Ω = 5.43 W.

Step 6: Calculate the power delivered by the battery.
The power (P) delivered by the battery is equal to the product of the current and the emf of the battery. So, P = I * V = 10.43 A * 12.0 V = 125.16 W.

So, the terminal voltage of the battery is 11.48 V, the power delivered to the load resistor is 119.32 W, the power delivered to the internal resistance of the battery is 5.43 W, and the power delivered by the battery is 125.16 W.

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