Activation energy (E ) and enthalpy of reaction(ΔH) for reaction A → B are 80 kJ mol and–20 KJ mol respectively. On adding catalystactivation energy decreases to 70 KJ mol thenenthalpy of reaction in presence of catalyst is :
Question
Activation energy (E ) and enthalpy of reaction(ΔH) for reaction A → B are 80 kJ mol and–20 KJ mol respectively. On adding catalystactivation energy decreases to 70 KJ mol thenenthalpy of reaction in presence of catalyst is :
Solution
To find the enthalpy of reaction in the presence of a catalyst, we can use the relationship between activation energy (Ea) and enthalpy of reaction (ΔH).
Given that the activation energy (Ea) for the reaction A → B is 80 kJ/mol and the enthalpy of reaction (ΔH) is -20 kJ/mol, we can use the equation:
ΔH = Ea + R*T
Where R is the gas constant and T is the temperature.
Now, when a catalyst is added, the activation energy decreases to 70 kJ/mol.
Substituting this new value of activation energy into the equation, we have:
ΔH = 70 kJ/mol + R*T
Since the enthalpy of reaction (ΔH) is independent of the presence of a catalyst, the enthalpy of reaction in the presence of the catalyst is still -20 kJ/mol.
Similar Questions
For a one step reaction, the activation energy for the forward reaction is 40.0 kJ mol-1, and the enthalpy of reaction is -20.0 kJ mol-1. Which statement below is true?Question 2Select one:a.The addition of a catalyst will produce a change in magnitude of the activation energy which is greater for the forward reaction than the reverse reaction.b.The value for the enthalpy of reaction would be decreased by addition of a catalyst.c.The reaction is endothermic.d.The reverse reaction is slower than the forward reaction (smaller rate constant).e.The reaction rate would be decreased by an increase in temperature.
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