Which of the following represents the x-intercepts and the vertex of the quadratic relation y = −x2 − 6x + 27? Question 5AnswerX-intercepts: x = 3, x = -9; Vertex (-3, 36) X-intercepts: x = -3, x = 9; Vertex (3, 36) X-intercepts: x = 3, x = -9; Vertex (-3, -36) X-intercepts: x = -3, x = 9; Vertex (3, -36)

The x-intercepts of a quadratic equation are found by setting y = 0 and solving for x.

So, we have 0 = -x^2 - 6x + 27.

This can be rewritten as x^2 + 6x - 27 = 0.

Factoring this equation gives (x - 3)(x + 9) = 0.

Setting each factor equal to zero gives the solutions x = 3 and x = -9.

The vertex of a quadratic equation is given by the point (-b/2a, f(-b/2a)), where a and b are the coefficients of the quadratic and linear terms, respectively, and f(x) is the function.

In this case, a = -1 and b = -6, so -b/2a = 3.

Substituting x = 3 into the equation gives y = -(3)^2 - 6*(3) + 27 = -9 - 18 + 27 = 0.

So, the vertex is (3, 0).

Therefore, the correct answer is "X-intercepts: x = 3, x = -9; Vertex (3, 0)". However, this option is not given in the choices. There might be a mistake in the question or the provided choices.