Sure, here is a step-by-step solution to the problem:

1. Read the value of N from the input. This represents the number of elements in the array A.
2. Read the value of K from the input. This represents the integer by which the sum of subarrays should be divisible.
3. Read the elements of the array A from the input and store them in a list or array.
4. Initialize a variable count to 0. This variable will keep track of the number of subarrays whose sum is divisible by K.
5. Initialize a dictionary or array called prefix_sum with a single key-value pair: (0, 1). This will be used to store the prefix sums and their frequencies.
6. Initialize a variable curr_sum to 0. This variable will keep track of the current prefix sum.
7. Iterate over each element in the array A.
a. Add the current element to curr_sum.
b. Calculate the remainder of curr_sum divided by K and store it in a variable called mod.
c. If mod is negative, add K to it to make it positive.
d. If mod exists as a key in the prefix_sum dictionary or array, increment count by the value associated with mod in prefix_sum.
e. If mod does not exist as a key in the prefix_sum dictionary or array, add it as a new key with a value of 1.
f. Increment the value associated with mod in the prefix_sum dictionary or array by 1.
8. Print the value of count as the output.

Here is the solution in Python:

```python
N, K = map(int, input().split())
A = list(map(int, input().split()))

count = 0
prefix_sum = {0: 1}
curr_sum = 0

for num in A:
curr_sum += num
mod = curr_sum % K
if mod

Question

Sure, here is a step-by-step solution to the problem:

1. Read the value of N from the input. This represents the number of elements in the array A.
2. Read the value of K from the input. This represents the integer by which the sum of subarrays should be divisible.
3. Read the elements of the array A from the input and store them in a list or array.
4. Initialize a variable count to 0. This variable will keep track of the number of subarrays whose sum is divisible by K.
5. Initialize a dictionary or array called prefix_sum with a single key-value pair: (0, 1). This will be used to store the prefix sums and their frequencies.
6. Initialize a variable curr_sum to 0. This variable will keep track of the current prefix sum.
7. Iterate over each element in the array A.
   a. Add the current element to curr_sum.
   b. Calculate the remainder of curr_sum divided by K and store it in a variable called mod.
   c. If mod is negative, add K to it to make it positive.
   d. If mod exists as a key in the prefix_sum dictionary or array, increment count by the value associated with mod in prefix_sum.
   e. If mod does not exist as a key in the prefix_sum dictionary or array, add it as a new key with a value of 1.
   f. Increment the value associated with mod in the prefix_sum dictionary or array by 1.
8. Print the value of count as the output.

Here is the solution in Python:

```python
N, K = map(int, input().split())
A = list(map(int, input().split()))

count = 0
prefix_sum = {0: 1}
curr_sum = 0

for num in A:
    curr_sum += num
    mod = curr_sum % K
    if mod < 0:
        mod += K
    if mod in prefix_sum:
        count += prefix_sum[mod]
    if mod in prefix_sum:
        prefix_sum[mod] += 1
    else:
        prefix_sum[mod] = 1

print(count)
```

This program takes the input values N, K, and the array A, and calculates the number of subarrays whose sum is divisible by K. The output is then printed as the final result.

Knowee AI · Accepted Answer

Sure, here is a step-by-step solution to the problem:

1. Read the value of N from the input. This represents the number of elements in the array A.
2. Read the value of K from the input. This represents the integer by which the sum of subarrays should be divisible.
3. Read the elements of the array A from the input and store them in a list or array.
4. Initialize a variable count to 0. This variable will keep track of the number of subarrays whose sum is divisible by K.
5. Initialize a dictionary or array called prefix_sum with a single key-value pair: (0, 1). This will be used to store the prefix sums and their frequencies.
6. Initialize a variable curr_sum to 0. This variable will keep track of the current prefix sum.
7. Iterate over each element in the array A.
   a. Add the current element to curr_sum.
   b. Calculate the remainder of curr_sum divided by K and store it in a variable called mod.
   c. If mod is negative, add K to it to make it positive.
   d. If mod exists as a key in the prefix_sum dictionary or array, increment count by the value associated with mod in prefix_sum.
   e. If mod does not exist as a key in the prefix_sum dictionary or array, add it as a new key with a value of 1.
   f. Increment the value associated with mod in the prefix_sum dictionary or array by 1.
8. Print the value of count as the output.

Here is the solution in Python:

```python
N, K = map(int, input().split())
A = list(map(int, input().split()))

count = 0
prefix_sum = {0: 1}
curr_sum = 0

for num in A:
    curr_sum += num
    mod = curr_sum % K
    if mod < 0:
        mod += K
    if mod in prefix_sum:
        count += prefix_sum[mod]
    if mod in prefix_sum:
        prefix_sum[mod] += 1
    else:
        prefix_sum[mod] = 1

print(count)
```

This program takes the input values N, K, and the array A, and calculates the number of subarrays whose sum is divisible by K. The output is then printed as the final result.

Given an array A of N integers and an integer K, write a program to print the number of subarrays in A whose sum is divisible by K. Sample input3 2 3 3 4Sample output3

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