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The self inductance L of a solenoid of length l and area of cross-section A, with a fixed number of turns N increases asl and A increasel decreases and A increasesl increases and A decreasesboth l and A decrease

Question

The self inductance L of a solenoid of length l and area of cross-section A, with a fixed number of turns N increases asl and A increasel decreases and A increasesl increases and A decreasesboth l and A decrease

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Solution

The self-inductance (L) of a solenoid is given by the formula:

L = μ0 * N² * A / l

where:

  • μ0 is the permeability of free space,
  • N is the number of turns,
  • A is the cross-sectional area, and
  • l is the length of the solenoid.

From this formula, we can see that:

  1. If the length (l) increases and the area (A) also increases, the self-inductance (L) will decrease. This is because l is in the denominator of the formula, so an increase in l will decrease L. However, A is in the numerator, so an increase in A will increase L. The net effect will depend on the relative changes in l and A.

  2. If the length (l) decreases and the area (A) increases, the self-inductance (L) will increase. This is because a decrease in l (which is in the denominator) will increase L, and an increase in A (which is in the numerator) will also increase L.

  3. If the length (l) increases and the area (A) decreases, the self-inductance (L) will decrease. This is because an increase in l will decrease L, and a decrease in A will also decrease L.

  4. If both the length (l) and the area (A) decrease, the self-inductance (L) will increase. This is because a decrease in l will increase L, and a decrease in A (which is in the numerator) will decrease L. However, the decrease in l will have a greater effect, so the net effect will be an increase in L.

This problem has been solved

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