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Given a BST with n (n>=2) nodes, find the kth common ancestor of nodes x and y in the given tree. Return -1 if kth ancestor does not exist.Nodes x and y will always be present in the input of a BST, and x != y.

Question

Given a BST with n (n>=2) nodes, find the kth common ancestor of nodes x and y in the given tree. Return -1 if kth ancestor does not exist.Nodes x and y will always be present in the input of a BST, and x != y.

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Solution

The problem you're asking about is a common one in computer science and involves understanding the structure and properties of Binary Search Trees (BSTs). Here's a step-by-step guide on how you might approach it:

  1. Understand the problem: The problem is asking to find the kth common ancestor of two nodes in a BST. An ancestor of a node in a BST is any node that is located on the path from the root to that node. A common ancestor of two nodes is a node that is an ancestor of both nodes. The kth common ancestor is the kth node on this common path, starting from the root.

  2. Create a function to find the path from root to a given node: This function will take the root of the BST and a node as input, and will return a list representing the path from the root to the node. This can be done using a simple recursive algorithm: start at the root, and if the node is less than the root, recurse on the left child; if the node is greater than the root, recurse on the right child; if the node is equal to the root, return the path up to this point.

  3. Find the paths for both nodes: Using the function from step 2, find the paths from the root to both nodes x and y.

  4. Find the common path: The common path of the two nodes is the longest prefix that the two paths share. This can be found by iterating over the two paths until a difference is found.

  5. Find the kth common ancestor: The kth common ancestor is simply the kth node in the common path. If k is greater than the length of the common path, return -1 as the kth ancestor does not exist.

  6. Implement and test: Finally, implement this algorithm in your chosen programming language and test it on a variety of test cases to ensure it works correctly.

Remember that this algorithm assumes that the BST property holds, i.e., for any node, all nodes in its left subtree are less than the node, and all nodes in its right subtree are greater than the node. If this property does not hold, the algorithm will not work correctly.

This problem has been solved

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