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Write a function that replaces an element of a list at a specific position (like in C).Prototype: def replace_in_list(my_list, idx, element):If idx is negative, the function should not modify anything, and returns the original listIf idx is out of range (> of number of element in my_list), the function should not modify anything, and returns the original listYou are not allowed to import any moduleYou are not allowed to use try/except

Question

Write a function that replaces an element of a list at a specific position (like in C).Prototype: def replace_in_list(my_list, idx, element):If idx is negative, the function should not modify anything, and returns the original listIf idx is out of range (> of number of element in my_list), the function should not modify anything, and returns the original listYou are not allowed to import any moduleYou are not allowed to use try/except

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Solution

To write a function that replaces an element of a list at a specific position, we can follow these steps:

  1. Define the function replace_in_list with three parameters: my_list, idx, and element.
  2. Check if idx is negative. If it is, return the original list my_list without modifying anything.
  3. Check if idx is greater than or equal to the length of my_list. If it is, return the original list my_list without modifying anything.
  4. If idx is within the valid range, replace the element at index idx in my_list with the new element.
  5. Return the modified my_list.

Here is the implementation of the function:

def replace_in_list(my_list, idx, element):
    if idx < 0:
        return my_list
    elif idx >= len(my_list):
        return my_list
    else:
        my_list[idx] = element
        return my_list

This function checks if the given index is valid and replaces the element accordingly. If the index is negative or out of range, it returns the original list without any modifications.

This problem has been solved

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