7 Indian, 4 Americans and 2 Germans are to be seated on 13 chairs for a photograph. If a photograph is clicked, what is the probability that in the photo no two Indians are together?

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This problem is quite complex and involves the use of combinatorics and probability. Here's a step-by-step solution:

Step 1: Calculate the total number of ways to arrange 13 people. This is simply 13!, or 13 factorial, which is 6,227,020,800.

Step 2: Calculate the number of ways to arrange 7 Indians such that no two are together. This can be done by first placing the 6 non-Indians (4 Americans and 2 Germans) in a row, which creates 7 spaces between and around them. These 7 spaces can be filled by the 7 Indians. The number of ways to arrange the 6 non-Indians is 6!, or 720, and the number of ways to arrange the 7 Indians is 7!, or 5,040. Therefore, the total number of ways to arrange all 13 people such that no two Indians are together is 720 * 5,040 = 3,628,800.

Step 3: Calculate the probability that no two Indians are together. This is the number of ways to arrange the people such that no two Indians are together divided by the total number of ways to arrange the people. Therefore, the probability is 3,628,800 / 6,227,020,800 = 0.00058275, or approximately 0.058%.

Please note that this solution assumes that all arrangements of people are equally likely, which may not be the case in reality.