Martin, a soup chef at a new restaurant, kept track of the first day's soup sales.Cup BowlSplit pea 4 2Chicken noodle 4 4Cream of mushroom 7 3What is the probability that a randomly selected soup was not chicken noodle or was not ordered in a cup?Simplify any fractions.Submit

To solve this problem, we first need to calculate the total number of soups sold.

From the table, we can see that:

• 4 cups and 2 bowls of split pea soup were sold, making a total of 6 split pea soups.
• 4 cups and 4 bowls of chicken noodle soup were sold, making a total of 8 chicken noodle soups.
• 7 cups and 3 bowls of cream of mushroom soup were sold, making a total of 10 cream of mushroom soups.

Adding these up, we find that a total of 6 + 8 + 10 = 24 soups were sold.

Next, we need to calculate the number of soups that were not chicken noodle or were not ordered in a cup.

The number of soups that were not chicken noodle is the total number of soups minus the number of chicken noodle soups, which is 24 - 8 = 16.

The number of soups that were not ordered in a cup is the total number of bowls sold. From the table, we can see that 2 bowls of split pea, 4 bowls of chicken noodle, and 3 bowls of cream of mushroom were sold, making a total of 2 + 4 + 3 = 9 bowls.

Therefore, the number of soups that were not chicken noodle or were not ordered in a cup is 16 + 9 = 25. However, we have double-counted the bowls of soup that were not chicken noodle. We need to subtract these from our total. There were 2 bowls of split pea and 3 bowls of cream of mushroom, making a total of 2 + 3 = 5 bowls that were not chicken noodle.

Subtracting these from our total, we find that the number of soups that were not chicken noodle or were not ordered in a cup is 25 - 5 = 20.

Finally, we can calculate the probability that a randomly selected soup was not chicken noodle or was not ordered in a cup by dividing the number of such soups by the total number of soups. This gives us a probability of 20 / 24 = 5 / 6.