To solve this problem, we need to use the equations of motion. We know that the helicopter is moving upward with a speed of 15 m/s and the package is released from the helicopter. So, initially, the package also has an upward speed of 15 m/s. But, the package is under the influence of gravity which will make it decelerate, stop and then accelerate downwards until it hits the ground.

The equation of motion we will use is:

s = ut + 0.5at^2

where:
s is the distance travelled,
u is the initial velocity,
t is the time, and
a is the acceleration.

Here, u = 15 m/s (upwards), t = 16 s, and a = -9.8 m/s^2 (downwards, as gravity acts downwards).

Substituting these values into the equation, we get:

s = 15*16 + 0.5*(-9.8)*(16)^2

Solving this, we get:

s = 240 - 1254.4

s = -1014.4 m

The negative sign indicates that the package has moved in the opposite direction to the initial direction of motion, which means it has moved downwards. So, the package was released 1014.4 m above the ground.

Question

To solve this problem, we need to use the equations of motion. We know that the helicopter is moving upward with a speed of 15 m/s and the package is released from the helicopter. So, initially, the package also has an upward speed of 15 m/s. But, the package is under the influence of gravity which will make it decelerate, stop and then accelerate downwards until it hits the ground.

The equation of motion we will use is:

s = ut + 0.5at^2

where:
s is the distance travelled,
u is the initial velocity,
t is the time, and
a is the acceleration.

Here, u = 15 m/s (upwards), t = 16 s, and a = -9.8 m/s^2 (downwards, as gravity acts downwards).

Substituting these values into the equation, we get:

s = 15*16 + 0.5*(-9.8)*(16)^2

Solving this, we get:

s = 240 - 1254.4

s = -1014.4 m

The negative sign indicates that the package has moved in the opposite direction to the initial direction of motion, which means it has moved downwards. So, the package was released 1014.4 m above the ground.

Knowee AI · Accepted Answer

To solve this problem, we need to use the equations of motion. We know that the helicopter is moving upward with a speed of 15 m/s and the package is released from the helicopter. So, initially, the package also has an upward speed of 15 m/s. But, the package is under the influence of gravity which will make it decelerate, stop and then accelerate downwards until it hits the ground.

The equation of motion we will use is:

s = ut + 0.5at^2

where:
s is the distance travelled,
u is the initial velocity,
t is the time, and
a is the acceleration.

Here, u = 15 m/s (upwards), t = 16 s, and a = -9.8 m/s^2 (downwards, as gravity acts downwards).

Substituting these values into the equation, we get:

s = 15*16 + 0.5*(-9.8)*(16)^2

Solving this, we get:

s = 240 - 1254.4

s = -1014.4 m

The negative sign indicates that the package has moved in the opposite direction to the initial direction of motion, which means it has moved downwards. So, the package was released 1014.4 m above the ground.

A package is released from a helicopter moving directly upward at 15 m/s. The package strikes the ground 16 s later. How high above the ground was the package when it was released?Neglect friction and express your answer in meters.

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