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You've been provided with a matrix mat comprising lowercase English letters, arranged in n rows and m columns. Your objective is to determine whether it's feasible to choose four distinct columns from left to right such that the first column contains 'p', the second contains 'l', the third contains 'a', and the fourth contains 'y'. If all these conditions can be met, the function should return 1; otherwise, it should return 0.Example 1:Input:n = 1m = 4mat = [ ['p', 'l', 'a', 'y'] ]Output:1Explanation:Choose the columns numbered 1,2,3,4 and they satisfy the required condition as they have the characters 'p' in column 1, 'l' in column 2, 'a' in column 3, 'y' in column 4.

Question

You've been provided with a matrix mat comprising lowercase English letters, arranged in n rows and m columns. Your objective is to determine whether it's feasible to choose four distinct columns from left to right such that the first column contains 'p', the second contains 'l', the third contains 'a', and the fourth contains 'y'. If all these conditions can be met, the function should return 1; otherwise, it should return 0.Example 1:Input:n = 1m = 4mat = [ ['p', 'l', 'a', 'y'] ]Output:1Explanation:Choose the columns numbered 1,2,3,4 and they satisfy the required condition as they have the characters 'p' in column 1, 'l' in column 2, 'a' in column 3, 'y' in column 4.

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Solution

To solve this problem, you can follow these steps:

  1. First, create four lists to store the column indices where 'p', 'l', 'a', and 'y' are found respectively.

  2. Iterate over the matrix. For each cell, check the character. If it's 'p', add the column index to the 'p' list. Do the same for 'l', 'a', and 'y'.

  3. After iterating over the matrix, you should have four lists with the column indices where each character is found. Now, you need to check if it's possible to choose four distinct columns such that the 'p' column is to the left of the 'l' column, the 'l' column is to the left of the 'a' column, and the 'a' column is to the left of the 'y' column.

  4. To do this, iterate over the 'p' list. For each 'p' column, find a 'l' column that is to the right of the 'p' column. If such a 'l' column is found, find an 'a' column that is to the right of the 'l' column. If such an 'a' column is found, find a 'y' column that is to the right of the 'a' column. If such a 'y' column is found, return 1 because it's possible to choose four distinct columns that satisfy the conditions.

  5. If no such columns are found after iterating over the 'p' list, return 0 because it's not possible to choose four distinct columns that satisfy the conditions.

This algorithm works because it checks all possible combinations of 'p', 'l', 'a', and 'y' columns. It returns 1 as soon as it finds a valid combination, or 0 if no valid combination is found after checking all possibilities.

This problem has been solved

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