A year 10 student walked 7m due East and thereafter moved 5m due south. She finally completed her journey by moving another 5m due East.i)          Represent this information in a vector diagramii)         Calculate the total distance covered by the studentiii)        Calculate the displacement from the starting point

i) To represent this information in a vector diagram, we can draw a horizontal line of length 7m to the right (east) from the starting point. Then, from the end of that line, we can draw a vertical line of length 5m downwards (south). Finally, from the end of the vertical line, we can draw another horizontal line of length 5m to the right (east). This will form a right-angled triangle.

ii) To calculate the total distance covered by the student, we can use the Pythagorean theorem. The horizontal distance covered is 7m + 5m = 12m, and the vertical distance covered is 5m. Using the Pythagorean theorem (a^2 + b^2 = c^2), where a and b are the horizontal and vertical distances respectively, and c is the total distance, we can find that c^2 = 12^2 + 5^2 = 144 + 25 = 169. Taking the square root of both sides, we find that c = √169 = 13m. Therefore, the total distance covered by the student is 13m.

iii) To calculate the displacement from the starting point, we need to find the straight-line distance from the starting point to the final position. This can be found using the Pythagorean theorem as well. The horizontal displacement is 7m + 5m = 12m, and the vertical displacement is -5m (since it is moving south). Using the Pythagorean theorem, we find that the displacement^2 = 12^2 + (-5)^2 = 144 + 25 = 169. Taking the square root of both sides, we find that the displacement = √169 = 13m. Therefore, the displacement from the starting point is 13m.