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A wall is of the form of a trapezium with height 4 m and parallel sides being 3 m and 5 m. What is the cost of painting the wall, if the rate of painting is Rs. 25/- per square metre?Choices:- 240 280 400 440

Question

A wall is of the form of a trapezium with height 4 m and parallel sides being 3 m and 5 m. What is the cost of painting the wall, if the rate of painting is Rs. 25/- per square metre?Choices:- 240 280 400 440

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Solution

To solve this problem, we first need to find the area of the trapezium. The formula for the area of a trapezium is:

Area = 1/2 * (sum of parallel sides) * height

Substituting the given values:

Area = 1/2 * (3m + 5m) * 4m Area = 1/2 * 8m * 4m Area = 16 square meters

Next, we need to find the cost of painting this area. The cost of painting is given as Rs. 25 per square meter. So, the total cost would be:

Cost = Area * Rate Cost = 16m^2 * Rs. 25/m^2 Cost = Rs. 400

So, the cost of painting the wall would be Rs. 400. Therefore, the correct answer is 400.

This problem has been solved

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