Consider the Python Listarr = [[123],[456]]What will the following code display?for i in range(len(rows)):   for j in range(len(columns)):      print(rows[i][j],end=" ")print("\n")

The code you provided seems to have some errors. The variables rows and columns are not defined, and the list arr is not used.

Assuming you meant to use arr instead of rows and columns, the corrected code would look like this:

arr = [[123],[456]]
for i in range(len(arr)):
   for j in range(len(arr[i])):
      print(arr[i][j],end=" ")
print("\n")

This code will print each element in the 2D list arr on the same line, separated by a space.

Here's how it works:

1. The outer loop for i in range(len(arr)): iterates over each sublist in arr.
2. The inner loop for j in range(len(arr[i])): iterates over each element in the current sublist.
3. print(arr[i][j],end=" ") prints the current element followed by a space, without moving to a new line.
4. After all elements have been printed, print("\n") prints a newline character, moving the cursor to the next line.

So, the output of this code will be:

123 456