Write a C program, which reads in the amount and prints the number of notes/coins of each denomination. Start with the highest denomination of Indian currency. 23761 x 20001 x 2001 x 1001 x 501 x 201 x 51 x 1
Question
Write a C program, which reads in the amount and prints the number of notes/coins of each denomination. Start with the highest denomination of Indian currency. 23761 x 20001 x 2001 x 1001 x 501 x 201 x 51 x 1
Solution
Sure, here is a simple C program that reads an amount and prints the number of notes/coins of each denomination in Indian currency. The denominations are 2000, 500, 200, 100, 50, 20, 10, 5, 2, and 1.
#include <stdio.h>
int main() {
int amount;
int denominations[10] = {2000, 500, 200, 100, 50, 20, 10, 5, 2, 1};
int notes[10] = {0};
printf("Enter the amount: ");
scanf("%d", &amount);
for(int i = 0; i < 10; i++) {
if(amount >= denominations[i]) {
notes[i] = amount / denominations[i];
amount = amount - notes[i] * denominations[i];
}
}
printf("\nNumber of notes/coins of each denomination:\n");
for(int i = 0; i < 10; i++) {
if(notes[i] != 0) {
printf("%d x %d\n", denominations[i], notes[i]);
}
}
return 0;
}
This program works by dividing the amount by each denomination in descending order, storing the quotient (number of notes/coins) and updating the amount to the remainder. It then prints the number of notes/coins for each denomination.
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