A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O2 gas to produce carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce 1.20mol of water. Be sure your answer has a unit symbol, if necessary, and round it to 3 significant digits.
Question
A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O2 gas to produce carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce 1.20mol of water. Be sure your answer has a unit symbol, if necessary, and round it to 3 significant digits.
Solution
The balanced chemical equation for the combustion of octane is:
2C8H18 + 25O2 -> 16CO2 + 18H2O
From the balanced equation, we can see that 25 moles of oxygen are required to produce 18 moles of water.
Therefore, to find out how many moles of oxygen are needed to produce 1.20 moles of water, we can set up a proportion:
25 moles O2 / 18 moles H2O = x moles O2 / 1.20 moles H2O
Solving for x gives us:
x = (25/18) * 1.20 = 1.67 moles O2
So, 1.67 moles of oxygen are needed to produce 1.20 moles of water.
Similar Questions
2 C8H18(l) + 25 O2(g) ----> 16 CO2(g) + 18 H2O(g)The above reaction is the reaction between gasoline (octane) and oxygen that occurs inside automobile engines. If 88.51 g of gasoline are burned, what volume, in L, of oxygen is needed if the pressure is 6.8 atm, and the temperature is 83.3°C?
Propane gas (C3H8) burns in oxygen to form carbon dioxide and water vapor according to the equation shown below. According to Gay-Lussac's law of combining volumes, one volume of propane will combine with ______ volume(s) of oxygen to produce a total of ______ volumes of products.C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)Multiple choice question.five; threefive; sevenone; sevenone; two
Consider the following balanced chemical equation for the combustion of propane.C3H8 + 5O2 ⟶ 3CO2 + 4H2OWhat volume of oxygen gas at 13.06 oC and 80.64 atm is needed for the complete combustion of 70.55 g of propane.
When methane is burned with oxygen, the products are carbon dioxide and water. If you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen, how many grams of carbon dioxide were produced in the reaction? 40 22 58 18 none of the above
Acetone (3CH3COCH3) undergoes combustion in the presence of oxygen to produce carbon dioxide and water: 2C3H6O+9O2→6CO2+6H2OIf you have 8 moles of acetone, calculate the moles of oxygen needed for complete combustion
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.