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Let the value of x be 2 in the environment outside theexpression. What is the value of the expression given below?(let ((x 3)(y (+ x 2)))(* x y))

Question

Let the value of x be 2 in the environment outside theexpression. What is the value of the expression given below?(let ((x 3)(y (+ x 2)))(* x y))

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Solution

The expression is written in Scheme, a dialect of Lisp. Here's how you evaluate it:

  1. The let expression creates a new scope where x is bound to 3 and y is bound to (+ x 2). In this scope, x is 3, not 2.

  2. The value of y is calculated as (+ x 2), which is (+ 3 2) because x is 3 in this scope. So, y is 5.

  3. The expression (* x y) is then evaluated as (* 3 5), which is 15.

So, the value of the expression is 15.

This problem has been solved

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