.If ‘x’ is the square of a natural number y, then ‘y' is*(a) The square of ’x’(b) √x and greater than or equal to x(c) An odd numberd) √x and less than or equal to x
Question
.If ‘x’ is the square of a natural number y, then ‘y' is*(a) The square of ’x’(b) √x and greater than or equal to x(c) An odd numberd) √x and less than or equal to x
Solution
The correct answer is (d) √x and less than or equal to x.
Here's why:
If 'x' is the square of a natural number 'y', it means that 'x' equals 'y' times 'y' (or 'y' squared).
To find 'y', you would take the square root of 'x' (√x).
Since 'y' is a natural number and 'x' is 'y' squared, 'y' will always be less than or equal to 'x'.
For example, if 'y' is 2, then 'x' would be 4. The square root of 'x' (or √4) is 2, which is equal to 'y'. And 'y' (2) is less than 'x' (4).
So, 'y' is √x and less than or equal to 'x'.
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