What will be the output of the program?int i = 1, j = 10; do { if(i > j) { break; } j--; } while (++i < 5); System.out.println("i = " + i + " and j = " + j); i = 6 and j = 6i = 5 and j = 6i = 6 and j = 5i = 5 and j = 5
Question
What will be the output of the program?int i = 1, j = 10; do { if(i > j) { break; } j--; } while (++i < 5); System.out.println("i = " + i + " and j = " + j); i = 6 and j = 6i = 5 and j = 6i = 6 and j = 5i = 5 and j = 5
Solution
The output of the program will be "i = 5 and j = 6".
Here's the step by step explanation:
- The initial values are i = 1 and j = 10.
- The do-while loop starts. The condition inside the loop is if i > j, then break. But at the start, i is not greater than j, so it doesn't break and proceeds to the next line which is j--, decrementing j by 1. So, j becomes 9.
- The condition for the do-while loop is ++i < 5, which means increment i by 1 and then check if it's less than 5. So, i becomes 2 and since 2 < 5, the loop continues.
- The same steps repeat, decrementing j by 1 and incrementing i by 1 each time, until i becomes 5.
- When i = 5, the loop condition ++i < 5 is no longer true (because 6 is not less than 5), so the loop ends.
- At this point, j has been decremented 4 times (from 10 to 6), so j = 6.
- Therefore, the final output is "i = 5 and j = 6".
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