Problem statementSend feedbackGiven a string ‘S’ find whether the given string is periodic or not.A string is said to be periodic if it repeats itself after a certain number of characters and the period of repetition is less than the size of the string.For example: Let ‘S’ be “ababab” we can clearly see that this string is periodic as ‘ab’ is repeated 3 times to make the string ‘S’.Detailed explanation ( Input/output format, Notes, Images )Constraints:1 <= T <= 501<= S.length<=10^5Where 'S.length' denotes the length of string ‘S’.The given string consists of lowercase English alphabets only.Time limit: 1 secSample Input 1:3xxxxxxaabbaaabbaabcbaSample Output 1:TrueTrueFalse Explanation of sample input 1 :Test Case 1:In the first test case, we can clearly see that the string has a repeating string ‘x’ 6 times. So we return trueTest Case 2:In the second test case, we can see that the string ‘aabba’ repeats twice to form the given string. Hence we return true,Test Case 3:In the third test case, we can see that there is no string which repeats itself to form the given string, hence we return false.Sample Input 2:2vwvnqpnchqikubzumubzumubzumubzumSample Output 2:FalseTrue

Given a string ‘S’ find whether the given string is periodic or not.A string is said to be periodic if it repeats itself after a certain number of characters and the period of repetition is less than the size of the string.For example: Let ‘S’ be “ababab” we can clearly see that this string is periodic as ‘ab’ is repeated 3 times to make the string ‘S’.

Define a 𝑘-periodic string as follows:A string 𝑠 is 𝑘-periodic if the length of the string |𝑠| is a multiple of 𝑘, and if you chop the string up into |𝑠|/𝑘 substrings of length 𝑘, then each of those substrings (except the first) is the same as the previous substring, but with its last character moved to the front.For example, the following string is 3-periodic:abccabbcaabcThe above string can break up into substrings abc, cab, bca, and abc, and each substring (except the first) is a right-rotation of the previous substring (abc -> cab -> bca -> abc)Given a string, determine the smallest k for which the string is k-periodic.InputEach input will consist of a single test case. Note that your program may be run multiple times on different inputs. The single line of input contains a string 𝑠 (1≤|𝑠|≤100) consisting only of lowercase letters.OutputOutput the integer 𝑘, which is the smallest 𝑘 for which the input string is 𝑘-periodic.Sample Input 1 Sample Output 1aaaaaaaa1Sample Input 2 Sample Output 2abbaabbaabba2Sample Input 3 Sample Output 3abcdef6Sample Input 4 Sample Output 4abccabbcaabc3

You are given a string word of size n, and an integer k such that k divides n.In one operation, you can pick any two indices i and j, that are divisible by k, then replace the substring of length k starting at i with the substring of length k starting at j. That is, replace the substring word[i..i + k - 1] with the substring word[j..j + k - 1].Return the minimum number of operations required to make word k-periodic.We say that word is k-periodic if there is some string s of length k such that word can be obtained by concatenating s an arbitrary number of times. For example, if word == “ababab”, then word is 2-periodic for s = "ab". Example 1:Input: word = "leetcodeleet", k = 4Output: 1Explanation:We can obtain a 4-periodic string by picking i = 4 and j = 0. After this operation, word becomes equal to "leetleetleet".Example 2:Input: word = "leetcoleet", k = 2Output: 3Explanation:We can obtain a 2-periodic string by applying the operations in the table below.i j word0 2 etetcoleet4 0 etetetleet6 0 etetetetet  Constraints:1 <= n == word.length <= 1051 <= k <= word.lengthk divides word.length.word consists only of lowercase English letters.

Write a Java program to check whether a substring(abc) appears before a period(.) within a given string

Given a string s, find the length of the longest substring without repeating characters.