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What is an equation for the line that passes through the points (–2, 3) and (2, 1)?

Question

What is an equation for the line that passes through the points (–2, 3) and (2, 1)?

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Solution

To find the equation of the line that passes through the points (-2, 3) and (2, 1), we need to follow these steps:

Step 1: Find the slope (m) of the line. The formula to find the slope when given two points (x1, y1) and (x2, y2) is:

m = (y2 - y1) / (x2 - x1)

Substituting the given points (-2, 3) and (2, 1) into the formula, we get:

m = (1 - 3) / (2 - (-2)) = -2 / 4 = -0.5

Step 2: Use the point-slope form of a line equation to find the equation of the line. The point-slope form of a line equation is:

y - y1 = m(x - x1)

We can use either of the given points for (x1, y1). Let's use (-2, 3):

y - 3 = -0.5(x - (-2))

Simplify the equation:

y - 3 = -0.5x - 1

Add 3 to both sides to solve for y:

y = -0.5x + 2

So, the equation of the line that passes through the points (-2, 3) and (2, 1) is y = -0.5x + 2.

This problem has been solved

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