If the ratio of the 5th5𝑡ℎ term from the beginning to the 5th5𝑡ℎ term from the end in the expansion of (2–√4+13√4)n24+134𝑛 is (6–√)5:165:1, then n𝑛 is equal toA17

The question seems to be incorrectly formatted, making it difficult to understand. However, I'll try to provide a general approach to solve such problems.

In the binomial expansion of (a+b)^n, the rth term from the beginning is given by:

T_r = nCr * a^(n-r+1) * b^(r-1)

And the rth term from the end is given by:

T_(n-r+2) = nCr * a^(r-1) * b^(n-r+1)

Given that the ratio of the 5th term from the beginning to the 5th term from the end is (6-√)5:165:1, we can set up the following equation:

(nC4 * a^(n-4) * b^4) / (nC4 * a^4 * b^(n-4)) = (6-√)5:165:1

Solving this equation will give you the value of n. However, without the correct values of a, b, and the ratio, it's impossible to provide a specific answer. Please check the question and provide the correct details.