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surface area, A𝐴, of a closed box is given by: A=2wb+2wh+2bh𝐴=2𝑤𝑏+2𝑤ℎ+2𝑏ℎ. Make b𝑏 the subject of the formula. A.b=A−whw+h𝑏=𝐴−𝑤ℎ𝑤+ℎB.b=2w+2hA−2wh𝑏=2𝑤+2ℎ𝐴−2𝑤ℎC.b=A−2wh2w+2h𝑏=𝐴−2𝑤ℎ2𝑤+2ℎD.b=A+2wh2w+2h

Question

surface area, A𝐴, of a closed box is given by: A=2wb+2wh+2bh𝐴=2𝑤𝑏+2𝑤ℎ+2𝑏ℎ. Make b𝑏 the subject of the formula. A.b=A−whw+h𝑏=𝐴−𝑤ℎ𝑤+ℎB.b=2w+2hA−2wh𝑏=2𝑤+2ℎ𝐴−2𝑤ℎC.b=A−2wh2w+2h𝑏=𝐴−2𝑤ℎ2𝑤+2ℎD.b=A+2wh2w+2h

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Solution

The question is asking to rearrange the formula for the surface area of a closed box to make 'b' the subject. The formula is given as A = 2wb + 2wh + 2bh.

To make 'b' the subject, we need to isolate 'b' on one side of the equation. Here are the steps:

  1. Subtract 2wh from both sides of the equation: A - 2wh = 2wb + 2bh
  2. Factor out 'b' from the right side of the equation: A - 2wh = 2wb + 2hb = b*(2w + 2h)
  3. Divide both sides of the equation by (2w + 2h) to solve for 'b': b = (A - 2wh) / (2w + 2h)

So, the correct answer is C. b = (A - 2wh) / (2w + 2h)

This problem has been solved

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