A 80.0kg person is on a scale in an elevator.a. What is the weight if the elevator is moving at constant speed? (2 marks)b. If the elevator is moving up at 6.0m/s2, what is the weight? (2 marks)c. If that person sees 560N as weight. Find the acceleration? (2 marks
Question
A 80.0kg person is on a scale in an elevator.a. What is the weight if the elevator is moving at constant speed? (2 marks)b. If the elevator is moving up at 6.0m/s2, what is the weight? (2 marks)c. If that person sees 560N as weight. Find the acceleration? (2 marks
Solution
a. If the elevator is moving at a constant speed, it means there is no acceleration. Therefore, the weight of the person remains the same. Weight is calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s² on Earth). So, the weight of the person is 80.0 kg * 9.8 m/s² = 784 N.
b. If the elevator is moving up at an acceleration of 6.0 m/s², the effective gravity inside the elevator is the sum of the actual gravity and the acceleration of the elevator. So, the effective gravity is 9.8 m/s² + 6.0 m/s² = 15.8 m/s². Therefore, the weight of the person in the elevator is 80.0 kg * 15.8 m/s² = 1264 N.
c. If the person sees 560 N as weight, it means the effective gravity inside the elevator is less than the actual gravity. The difference is due to the acceleration of the elevator. So, the effective gravity is 560 N / 80.0 kg = 7.0 m/s². Therefore, the acceleration of the elevator is 9.8 m/s² - 7.0 m/s² = 2.8 m/s² downwards.
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