The area of a rectangle is given by 6x2y + 4y2x andthe width of the rectangle is given by 2xy. Find theperimeter of rectangle.
Question
The area of a rectangle is given by 6x2y + 4y2x andthe width of the rectangle is given by 2xy. Find theperimeter of rectangle.
Solution
To find the perimeter of the rectangle, we first need to find the length of the rectangle. We know that the area of a rectangle is given by the formula:
Area = Length * Width
Given that the area is 6x^2y + 4y^2x and the width is 2xy, we can find the length by rearranging the formula to:
Length = Area / Width
Substituting the given values, we get:
Length = (6x^2y + 4y^2x) / 2xy
Simplify the equation by dividing each term by 2xy:
Length = 3x + 2y
Now that we have the length and the width of the rectangle, we can find the perimeter using the formula:
Perimeter = 2 * (Length + Width)
Substituting the values we found:
Perimeter = 2 * ((3x + 2y) + 2xy)
Simplify the equation to get the perimeter:
Perimeter = 2 * (3x + 2y + 2xy)
So, the perimeter of the rectangle is 2 * (3x + 2y + 2xy).
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