In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:
Question
In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:
Solution
To solve this problem, we need to understand the relative speeds of A, B, and C.
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In a 100m race, A beats B by 10m. This means when A runs 100m, B runs 90m. So, the speed ratio of A to B is 100:90 or 10:9.
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Similarly, in a 100m race, A beats C by 13m. This means when A runs 100m, C runs 87m. So, the speed ratio of A to C is 100:87.
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Now, we need to find the speed ratio of B to C. We know that A:B = 10:9 and A:C = 100:87. We can equate these to find B:C.
10/9 = 100/87 B/C = (1087)/(9100) = 29/30
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This means when B runs 30m, C runs 29m.
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In a 180m race, how far will C run when B runs the whole distance? We can set up a proportion to find out:
30/29 = 180/x x = (29*180)/30 = 174m
So, in a 180m race, B will beat C by 180m - 174m = 6m.
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