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Solve the quadratic by factoring.x, squared, plus, 10, equals, 7, x, plus, 4x 2 +10=7x+4

Question

Solve the quadratic by factoring.x, squared, plus, 10, equals, 7, x, plus, 4x 2 +10=7x+4

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Solution

First, let's rewrite the equation in standard form, which is ax^2 + bx + c = 0.

The given equation is x^2 + 10 = 7x + 4.

Rearrange the equation to get x^2 - 7x + 10 - 4 = 0.

This simplifies to x^2 - 7x + 6 = 0.

Now, we can factor the quadratic equation. We're looking for two numbers that multiply to 6 (the c term) and add to -7 (the b term).

Those numbers are -6 and -1, because -6*-1 = 6 and -6 + -1 = -7.

So, we can write the factored form of the equation as (x - 6)(x - 1) = 0.

Setting each factor equal to zero gives the solutions to the equation:

x - 6 = 0 => x = 6

x - 1 = 0 => x = 1

So, the solutions to the equation x^2 + 10 = 7x + 4 are x = 6 and x = 1.

This problem has been solved

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