To solve this problem, we need to understand the pattern of how the cows are being cleaned. The farmer cleans K cows from the front and K cows from the end. This means that in each turn, 2*K cows are cleaned.

Here are the steps to solve this problem:

1. First, calculate the total number of cows that will be cleaned in each turn, which is 2*K.

2. Then, calculate the total number of turns it will take to clean all the cows. This can be done by dividing the total number of cows N by the number of cows cleaned in each turn (2*K). If N is not exactly divisible by 2*K, then we need to add 1 to the total number of turns because the last turn will clean the remaining cows.

3. The position of the cow that will get the last turn to be cleaned is the total number of turns multiplied by K. This is because in each turn, K cows from the front are cleaned first.

4. If the position of the cow is greater than N, then the position should be N. This is because there are only N cows, so the position cannot be greater than N.

5. Finally, print the position of the cow that will get the last turn to be cleaned.

Here is a Python code snippet that implements these steps:

```python
t = int(input())
for _ in range(t):
N, K = map(int, input().split())
turns = (N + 2*K - 1) // (2*K)
position = turns * K
if position N:
position = N
print(position)
```

This code first reads the number of test cases. For each test case, it reads the number of cows N and the number of cows the farmer is selecting from front and end K. It then calculates the total number of turns and the position of the cow that will get the last turn to be cleaned. If the position is greater than N, it sets the position to N. Finally, it prints the position.

Question

To solve this problem, we need to understand the pattern of how the cows are being cleaned. The farmer cleans K cows from the front and K cows from the end. This means that in each turn, 2*K cows are cleaned.

Here are the steps to solve this problem:

1. First, calculate the total number of cows that will be cleaned in each turn, which is 2*K.

2. Then, calculate the total number of turns it will take to clean all the cows. This can be done by dividing the total number of cows N by the number of cows cleaned in each turn (2*K). If N is not exactly divisible by 2*K, then we need to add 1 to the total number of turns because the last turn will clean the remaining cows.

3. The position of the cow that will get the last turn to be cleaned is the total number of turns multiplied by K. This is because in each turn, K cows from the front are cleaned first.

4. If the position of the cow is greater than N, then the position should be N. This is because there are only N cows, so the position cannot be greater than N.

5. Finally, print the position of the cow that will get the last turn to be cleaned.

Here is a Python code snippet that implements these steps:

```python
t = int(input())
for _ in range(t):
    N, K = map(int, input().split())
    turns = (N + 2*K - 1) // (2*K)
    position = turns * K
    if position > N:
        position = N
    print(position)
```

This code first reads the number of test cases. For each test case, it reads the number of cows N and the number of cows the farmer is selecting from front and end K. It then calculates the total number of turns and the position of the cow that will get the last turn to be cleaned. If the position is greater than N, it sets the position to N. Finally, it prints the position.

Knowee AI · Accepted Answer