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Exercise 2: (3 POINTS) Suppose the domain of the propositional function ๐‘ƒ(๐‘ฅ, ๐‘ฆ) consists ofpairs ๐‘ฅ and ๐‘ฆ, where ๐‘ฅ is โˆ’1, 0 or 1 and ๐‘ฆ is 0 or 2. Write out the propositions usingdisjunctions and conjunctions:a) ยฌโˆ€๐‘ฅ๐‘ƒ(๐‘ฅ, 2) (1 POINT)b) โˆ€๐‘ฆโˆƒ๐‘ฅ๐‘ƒ(๐‘ฅ, ๐‘ฆ)

Question

Exercise 2: (3 POINTS) Suppose the domain of the propositional function ๐‘ƒ(๐‘ฅ, ๐‘ฆ) consists ofpairs ๐‘ฅ and ๐‘ฆ, where ๐‘ฅ is โˆ’1, 0 or 1 and ๐‘ฆ is 0 or 2. Write out the propositions usingdisjunctions and conjunctions:a) ยฌโˆ€๐‘ฅ๐‘ƒ(๐‘ฅ, 2) (1 POINT)b) โˆ€๐‘ฆโˆƒ๐‘ฅ๐‘ƒ(๐‘ฅ, ๐‘ฆ)

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Solution

a) ยฌโˆ€๐‘ฅ๐‘ƒ(๐‘ฅ, 2) translates to "It is not the case that for all x, P(x, 2) is true." In terms of disjunctions and conjunctions, this can be written as:

ยฌP(-1, 2) โˆจ ยฌP(0, 2) โˆจ ยฌP(1, 2)

This means that at least one of the propositions P(-1, 2), P(0, 2), or P(1, 2) is not true.

b) โˆ€๐‘ฆโˆƒ๐‘ฅ๐‘ƒ(๐‘ฅ, ๐‘ฆ) translates to "For all y, there exists an x such that P(x, y) is true." In terms of disjunctions and conjunctions, this can be written as:

(P(-1, 0) โˆจ P(0, 0) โˆจ P(1, 0)) โˆง (P(-1, 2) โˆจ P(0, 2) โˆจ P(1, 2))

This means that for each y (0 and 2), there is at least one x (-1, 0, or 1) that makes the proposition P(x, y) true.

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