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Time left 0:38:55Question 5Tries remaining: 1Marked out of 1.00Flag questionTipsQuestion textTwo point charges, q1 and q2 are separated by a distance d. For convenience, we will say that q1 is at the origin (0,0) on a coordinate system, q2 is at (d,0) and a reference point p is directly above q2 at a distance h at point (d,h). q1  has value 1μ𝜇C and q2  has value 8μ𝜇C. Take d= 1.1m and h= 0.7m.Note k=9×109Nm2/C2𝑘=9×109𝑁𝑚2/𝐶2   What is the magnitude of force (in N) between q1 and q2? Note:  Give your answer to two decimal places, and do not enter the units.

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Time left 0:38:55Question 5Tries remaining: 1Marked out of 1.00Flag questionTipsQuestion textTwo point charges, q1 and q2 are separated by a distance d. For convenience, we will say that q1 is at the origin (0,0) on a coordinate system, q2 is at (d,0) and a reference point p is directly above q2 at a distance h at point (d,h). q1  has value 1μ𝜇C and q2  has value 8μ𝜇C. Take d= 1.1m and h= 0.7m.Note k=9×109Nm2/C2𝑘=9×109𝑁𝑚2/𝐶2   What is the magnitude of force (in N) between q1 and q2? Note:  Give your answer to two decimal places, and do not enter the units.

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Solution

The force between two charges is given by Coulomb's law, which states:

F = k * |q1*q2| / r^2

where: F is the force between the charges, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the amounts of charge, r is the distance between the charges.

Given: q1 = 1μC = 1 x 10^-6 C, q2 = 8μC = 8 x 10^-6 C, d = 1.1 m.

Substituting these values into the equation gives:

F = (9 x 10^9 Nm^2/C^2) * |(1 x 10^-6 C) * (8 x 10^-6 C)| / (1.1 m)^2 = (9 x 10^9 Nm^2/C^2) * (8 x 10^-12 C^2) / 1.21 m^2 = 59.50 N.

So, the magnitude of the force between q1 and q2 is 59.50 N.

This problem has been solved

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