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Here is a sketch of a 2py orbital:This sketch is about 800pm wide.The coordinate (x, y, and z) axes are also shown.You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse.Suppose an atom with its nucleus at the origin has an electron in a 2py orbital. Complete each row of the table below by deciding how PA, the probability of finding the electron at point A, compares to PB, the probability of finding the electron at point B.point A point B compare PA to PB100 pm below the nucleus along the -z axis. 100 pm to the right of the nucleus, along the +x axis. <PAPB=PAPB>PAPB100 pm in front of the nucleus, along the -y axis. 100 pm above the nucleus, along the +z axis. <PAPB=PAPB>PAPB100 pm behind the nucleus, along the +y axis. 100 pm to the left of the nucleus, along the -x axis. <PAPB=PAPB>PAPB

Question

Here is a sketch of a 2py orbital:This sketch is about 800pm wide.The coordinate (x, y, and z) axes are also shown.You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse.Suppose an atom with its nucleus at the origin has an electron in a 2py orbital. Complete each row of the table below by deciding how PA, the probability of finding the electron at point A, compares to PB, the probability of finding the electron at point B.point A point B compare PA to PB100 pm below the nucleus along the -z axis. 100 pm to the right of the nucleus, along the +x axis. <PAPB=PAPB>PAPB100 pm in front of the nucleus, along the -y axis. 100 pm above the nucleus, along the +z axis. <PAPB=PAPB>PAPB100 pm behind the nucleus, along the +y axis. 100 pm to the left of the nucleus, along the -x axis. <PAPB=PAPB>PAPB

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Solution

The 2py orbital is oriented along the y-axis, with lobes in the positive and negative y directions. The electron density is concentrated along the y-axis and there is a nodal plane along the xz plane. This means that the probability of finding an electron along the x or z axis is essentially zero.

  1. Point A is 100 pm below the nucleus along the -z axis and point B is 100 pm to the right of the nucleus, along the +x axis. Since both points are along the xz plane where there is a nodal plane, the probability of finding an electron at both points is essentially zero. Therefore, PA = PB.

  2. Point A is 100 pm in front of the nucleus, along the -y axis and point B is 100 pm above the nucleus, along the +z axis. The probability of finding an electron at point A is higher because it lies along the y-axis where the 2py orbital is oriented. The probability of finding an electron at point B is essentially zero because it lies along the xz nodal plane. Therefore, PA > PB.

  3. Point A is 100 pm behind the nucleus, along the +y axis and point B is 100 pm to the left of the nucleus, along the -x axis. Similar to the previous comparison, the probability of finding an electron at point A is higher because it lies along the y-axis where the 2py orbital is oriented. The probability of finding an electron at point B is essentially zero because it lies along the xz nodal plane. Therefore, PA > PB.

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