The sum of the coefficients of the expansion of any binomial expression (a + b)^n is found by substituting 1 for both a and b in the expression. This is because the coefficients are found by multiplying the terms by the binomial coefficients, which are the numbers in Pascal's triangle.

So, for the expression (2x - 1)^20, we substitute 1 for 2x and -1 for -1 to get:

(1 + (-1))^20 = 0^20 = 0

So, the sum of the coefficients of the expansion of (2x - 1)^20 is 0.

Question

The sum of the coefficients of the expansion of any binomial expression (a + b)^n is found by substituting 1 for both a and b in the expression. This is because the coefficients are found by multiplying the terms by the binomial coefficients, which are the numbers in Pascal's triangle.

So, for the expression (2x - 1)^20, we substitute 1 for 2x and -1 for -1 to get:

(1 + (-1))^20 = 0^20 = 0

So, the sum of the coefficients of the expansion of (2x - 1)^20 is 0.

Knowee AI · Accepted Answer

The sum of the coefficients of the expansion of any binomial expression (a + b)^n is found by substituting 1 for both a and b in the expression. This is because the coefficients are found by multiplying the terms by the binomial coefficients, which are the numbers in Pascal's triangle.

So, for the expression (2x - 1)^20, we substitute 1 for 2x and -1 for -1 to get:

(1 + (-1))^20 = 0^20 = 0

So, the sum of the coefficients of the expansion of (2x - 1)^20 is 0.

What is the sum of the coefficients of the expansion of (2x –1)²⁰?

Question

Solution

Similar Questions

Upgrade your grade with Knowee