Determine the y-intercept of the following equation.left bracket, minus, x, plus, 3, right bracket, left bracket, x, minus, 4, right bracket, equals, y(−x+3)(x−4)=yAnswerMultiple Choice Answersleft bracket, minus, 3, comma, 0, right bracket, and , left bracket, 4, comma, 0, right bracket(−3,0) and (4,0)left bracket, 0, comma, minus, 12, right bracket(0,−12)left bracket, 0, comma, 3, right bracket, and , left bracket, 0, comma, 4, right bracket(0,3) and (0,4)left bracket, 3, comma, 0, right bracket, and , left bracket, 4, comma, 0, right bracket(3,0) and (4,0)left bracket, 0, comma, 12, right bracket(0,12)left bracket, minus, 12, comma, 0, right bracket(−12,0)
Question
Determine the y-intercept of the following equation.left bracket, minus, x, plus, 3, right bracket, left bracket, x, minus, 4, right bracket, equals, y(−x+3)(x−4)=yAnswerMultiple Choice Answersleft bracket, minus, 3, comma, 0, right bracket, and , left bracket, 4, comma, 0, right bracket(−3,0) and (4,0)left bracket, 0, comma, minus, 12, right bracket(0,−12)left bracket, 0, comma, 3, right bracket, and , left bracket, 0, comma, 4, right bracket(0,3) and (0,4)left bracket, 3, comma, 0, right bracket, and , left bracket, 4, comma, 0, right bracket(3,0) and (4,0)left bracket, 0, comma, 12, right bracket(0,12)left bracket, minus, 12, comma, 0, right bracket(−12,0)
Solution
The y-intercept of an equation is the point where the line crosses the y-axis. This is when x = 0.
So, to find the y-intercept of the equation (−x+3)(x−4)=y, we substitute x = 0 into the equation:
y = (−0+3)(0−4) y = (3)(-4) y = -12
So, the y-intercept of the equation is (0, -12). Therefore, the correct answer is (0, -12).
Similar Questions
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What is the x - intercept of the equation 3x + 4y = 12?y = 3x = 4y = -3x = -4
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Let’s try another that we need to factor.Problemy=x2−5x−14𝑦=𝑥2−5𝑥−14 SolutionList out the factors of −14−14:−1−1 and 141411 and 22 and −2−2 and Which of these pairs add up to −5−5? and Now we’ll write this in factored form:y=(x+𝑦=(𝑥+ )(x−)(𝑥− ))To find the zeros/solutions/x𝑥-intercepts, set each factor equal to 00 and solve for x𝑥.x+𝑥+ =0=0 and x−𝑥− =0=0x=𝑥= and x=𝑥= Our two solutions are (( ,, )) and (( ,, )) (Enter from least to greatest.)We can now use these to find the vertex. Remember the x𝑥-value of the vertex, as well as the axis of symmetry, is halfway between the two solutions.−2+72=52=2.5−2+72=52=2.5x=2.5𝑥=2.5 is our axis of symmetry. We’ll substitute this value into our original equation to find the y𝑦-value of the vertex.y=(𝑦=( )2−5()2−5( )−14)−14y=6.25−12.5−14𝑦=6.25−12.5−14y=−20.25𝑦=−20.25The vertex is (( ,, )).Finally, state the domain and range.Domain: All real numbers (as with all quadratic functions)Range: y≥𝑦≥ CheckQuestion 3
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