How many positive divisors does the number 202410 have?

To find the number of positive divisors of the number 202410, we first need to find its prime factorization.

1. Prime factorization of 202410:

202410 = 2 * 5 * 101 * 401

2. Now, we count the number of times each prime number appears in the factorization and add 1 to each count:

For 2, it appears once, so we get 1 + 1 = 2 For 5, it appears once, so we get 1 + 1 = 2 For 101, it appears once, so we get 1 + 1 = 2 For 401, it appears once, so we get 1 + 1 = 2

3. Finally, we multiply these counts together to get the total number of positive divisors:

2 * 2 * 2 * 2 = 16

So, the number 202410 has 16 positive divisors.

To find the number of positive divisors of 202410, we first need to find its prime factorization.

1. Prime factorization of 202410:

   202410 = 2 * 5 * 101 * 401

2. Now, we count the number of times each prime number appears in the factorization and add 1 to each count:

   For 2, it appears once, so we have 1 + 1 = 2.

   For 5, it appears once, so we have 1 + 1 = 2.

   For 101, it appears once, so we have 1 + 1 = 2.

   For 401, it appears once, so we have 1 + 1 = 2.

3. Finally, we multiply these counts together to get the total number of positive divisors:

   2 * 2 * 2 * 2 = 16

So, the number 202410 has 16 positive divisors.