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Consider the function y = x4 + 1.On the interval (−∞, 0) the derivative y′ is(A) negative and the function is decreasing(B) positive and the function is increasing(enter A/B)On the interval (0, ∞) the derivative y′ is(A) negative and the function is decreasing(B) positive and the function is increasing(enter A/B)

Question

Consider the function y = x4 + 1.On the interval (−∞, 0) the derivative y′ is(A) negative and the function is decreasing(B) positive and the function is increasing(enter A/B)On the interval (0, ∞) the derivative y′ is(A) negative and the function is decreasing(B) positive and the function is increasing(enter A/B)

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Solution

First, let's find the derivative of the function y = x^4 + 1. The derivative, y', is 4x^3.

On the interval (-∞, 0), if we substitute any negative number for x in the derivative, the result will be negative because a negative number to an odd power is negative. Therefore, the derivative y' is negative and the function is decreasing on this interval. So, the answer is (A).

On the interval (0, ∞), if we substitute any positive number for x in the derivative, the result will be positive because a positive number to any power is positive. Therefore, the derivative y' is positive and the function is increasing on this interval. So, the answer is (B).

This problem has been solved

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