If a graph has 'n' vertices, what is the maximum size of the matrix required to represent its transitive closure using the Warshall algorithm?
Question
If a graph has 'n' vertices, what is the maximum size of the matrix required to represent its transitive closure using the Warshall algorithm?
Solution
The maximum size of the matrix required to represent the transitive closure of a graph with 'n' vertices using the Warshall algorithm is n x n. This is because the Warshall algorithm uses a square matrix for its computation. Each row and each column of the matrix represents a vertex in the graph. Therefore, for 'n' vertices, we would need a matrix of size n x n.
Similar Questions
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Dynamic Programming: Warshall’s algorithmApply Warshall’s algorithm to find the transitive closure of the digraph defined by thefollowing adjacency matrix:[[0,0,0,1],[0,0,1,0],[0,0,0,1],[0,0,0,0]]
The Warshall algorithm uses ____ nested loops to compute the transitive closure.
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Consider a directed graph with six vertices. The initial adjacency matrix is given below. After applying the Warshall algorithm, how many entries in the resulting adjacency matrix will be '1'?Initial Adjacency Matrix: | 1 2 3 4 5 6----------------1 | 0 1 0 1 0 02 | 0 0 1 0 0 03 | 0 0 0 0 1 14 | 0 0 0 0 0 05 | 0 0 0 1 0 06 | 0 0 0 0 0 0
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